IBM SVC SDD DRIVER
May 15, 2020 | by admin
Thats because when it comes to all things related to storage performance, more often than not, “it depends”. You lose the parity disk’s worth of capacity with parity data. Optimal configurations require at least 4 arrays, to ensure maximal core usage. Is the workload random or sequential? An array has a defined strip size.
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Within the SVC softare that runs on the V, we have worked for many years over 12 now on making the code path and per core processing ihm consistent as possible. In this case, 8 data disks, so 8x kb 2MB. Here your reads will come from just one disk in the array. Since arrays can be accessed through both nodes in the V system, 4 is enough, on each node, scv array will be assigned and processed through one core.
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When a RAID-5 array has to write to a strip, it needs to read the existing strip, read the existing sdr strip, update the existing strip read modify, write and then calculate the new parity. How to find the IBM Looking at IBM Spect With V, always configure at least 4 arrays, and if possible, multiples of 4.
Any questions, feel free to ask. Type in a Name: If the host then issues a single 2MB write, we can write across all 8 strips, in memory calculate the parity sdf write that too. Do you need the most MB or GB per second? This is commonly referred to as “full stride writes” or “full strip writes” – essentially you are writing all new data across all disk that make up the array, and in memory, calculating the new parity data. Find the duplicate idea: Is the host optimally configured for the storage system?
Optimal configurations require at least 4 arrays, to ensure maximal core usage.
IBM Subsystem Device Driver Path Control Module (SDDPCM) – United States
In Part 3, I will discuss storage pool configurations, mdisk groups in old SVC parlance And finally in Part 4, I will discuss volume vdisk and host configurations.
Part 1 – Summary. An array has a defined strip size.
Is the workload random or sequential? Previous Entry Main Next Entry.
To write a ful stride, we need to write to all data disks. Now we only have to use 9x kb writes, and no reads.
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That means you need at least 4 arrays per V to get maximal CPU core performance. Provide a reason for quarantining this blog entry optional: There are so many factors that contribute to getting the best performance out of a storage system, that it really does depend on what you are trying to achieve. You lose the parity disk’s worth sdr capacity with parity data.
I was once creditied in an IBM Redbook, with the comment: Lets say the strip is kb. What striping is happening where? Thats because when it comes to all things related to storage performance, more often than not, “it depends”. Sequential Processing When it sdv to sequential reads and writes, here you can get the benefits of both capacity and bandwidth.